by Buz Groshong » Mon Aug 02, 2010 4:12 pm
by mrchad9 » Mon Aug 02, 2010 5:37 pm
Buz Groshong wrote:One factor in your better gas milage out west might be the lack of the additives in the gasoline that are required by EPA in certain areas of the country to reduce pollution.
by Ze » Mon Aug 02, 2010 8:27 pm
Day Hiker wrote:On a grade, the power-to-fuel efficiency would actually be higher, assuming speed and gear ratio (thus engine speed) remains constant. This is because of the relationship between fuel and power (roughly y=mx+b) that I mentioned before, where y is the fuel usage and x is the engine's load, at a given rpm. It's not proportional (b>0), but it is roughly linear (x^1) for a typical engine. So at a given engine speed, at higher power output, the engine is more efficient, basically because it takes a certain amount of power to just spin the engine, under no load. So the higher the load, the higher the proportion of fuel energy is going to the load.
by Day Hiker » Mon Aug 02, 2010 11:37 pm
Ze wrote:Day Hiker wrote:On a grade, the power-to-fuel efficiency would actually be higher, assuming speed and gear ratio (thus engine speed) remains constant. This is because of the relationship between fuel and power (roughly y=mx+b) that I mentioned before, where y is the fuel usage and x is the engine's load, at a given rpm. It's not proportional (b>0), but it is roughly linear (x^1) for a typical engine. So at a given engine speed, at higher power output, the engine is more efficient, basically because it takes a certain amount of power to just spin the engine, under no load. So the higher the load, the higher the proportion of fuel energy is going to the load.
Yes makes sense. And we could break down the power requirements into maybe 3 portions? Internal friction / resistance (F), air drag (D), and gravity (G). Total power needed to generate T = F + D + G. Here's the comparison: One car drives 40 miles at 80 mph flat. Another drives 20 miles up 5% grade at 80 and down 20 miles at 5% at 80mph.
In both cases, the same amount of internal friction and and air drag forces must be overcome (F+D). In the uphill / downhill case, there is also work against gravity (i.e external work) uphill. Downhill, gravity assists against friction & drag. (+G, then -G).
At 80 mph downhill, as long as gravitational force is less than friction and drag forces G < (F+D), then energy won't be lost through braking. The +/- gravitational work will cancel out, and you should have ~ the same energy required in both cases.
However, as others are saying, drag will vary with altitude, so if all else is equal then this would reduce drag in the uphill / downhill case.
Users browsing this forum: No registered users and 0 guests